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Hawkesbury Island

Coordinates: 53°36′30″N 129°2′0″W / 53.60833°N 129.03333°W / 53.60833; -129.03333
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This is an old revision of this page, as edited by Skookum1 (talk | contribs) at 13:29, 16 February 2009 (uninhabited islands with no settlements are irrelevant to RD categories, which are not and should not be used as geographic region-cats). The present address (URL) is a permanent link to this revision, which may differ significantly from the current revision.

Hawkesbury Island is an island in British Columbia, Canada. It is located in Douglas Channel, an inlet of [[Hecate Strait Hawkesbury Island is 43 kilometres (27 mi) long and ranges in width from 3 kilometres (1.9 mi) to 19 kilometres (12 mi). It is 412 square kilometres (159 sq mi) in area.[1]

Hawkesbury Island was named by George Vancouver for Charles Jenkinson, Baron Hawkesbury, President of the Board of Trade 1786-1804.[2]

References

  1. ^ Hawkesbury Island, The Columbia Gazetteer of North America
  2. ^ "Hawkesbury Island". BC Geographical Names.

53°36′30″N 129°2′0″W / 53.60833°N 129.03333°W / 53.60833; -129.03333

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