Utilization period
The utilization period or useful life of a power plant is equal to the quotient of the total work in a period of time and the bottleneck performance of the plant.
The utilization period is given in full load hours per year . For the utilization times of different types of power plants in Germany see the article full load hour .
Calculation example
A calculation example: A wind power plant (WKA) stands still for 3 months, for 4 months it provides 30 percent of its nominal output, 5 months 70 percent and 1 month 100 percent.
Degree of utilization: 3/12 0 + 4/12 0.3 + 5/12 0.7 + 1/12 1 = 0.475
A wind turbine that would work constantly with 47.5% of its nominal output all year round generated the same amount of electricity as the one described above. A utilization of 47.5% corresponds to a utilization period of 8760 · 0.475 = 4161 full load hours per year.
Individual evidence
- ↑ Lexicon: Duration of use. (No longer available online.) Kernfragen.de, archived from the original on November 10, 2013 ; Retrieved November 4, 2013 . Info: The archive link was inserted automatically and has not yet been checked. Please check the original and archive link according to the instructions and then remove this notice.
- ↑ Lexicon: Bottleneck performance. (No longer available online.) Kernfragen.de, archived from the original on November 10, 2013 ; Retrieved November 4, 2013 . Info: The archive link was inserted automatically and has not yet been checked. Please check the original and archive link according to the instructions and then remove this notice.
- ↑ Erich Hau: Wind power plants: Basics, technology, use, economy . Springer, 2008, ISBN 978-3-540-72150-5 , pp. 580 ( limited preview in Google Book search).
