Celeste Contín
| Country (sports) |  Argentina |
|---|---|
| Born | 17 February 1978 |
| Prize money | $68,132 |
| Singles | |
| Highest ranking | No. 236 (1998/07/20) |
| Doubles | |
| Highest ranking | No. 142 (1997/09/08) |
Celeste Contín (born 17 February 1978) is a former professional tennis player from Argentina.
Biography
Contín, who reached a career high singles ranking of 236 in the world, competed mostly on the ITF circuit, winning eight singles titles. She also has a career win over Justine Henin, who she beat at an ITF tournament in a Spartanburg in 1998.
Her career included a Fed Cup appearance for Argentina in 1998, a World Group II Play-off tie against Australia in Canberra. She played in the second singles rubber, which she lost to Nicole Pratt.[1]
On the WTA Tour, Contín's best performance came when she won her way through to the round of the 16 at Bogota in 1999, having made the main draw as a qualifier.
See also
References
- ^ "La Argentina empezó muy mal con Australia". La Nacion (in Spanish). 26 July 1998.
External links
- Celeste Contín at the Women's Tennis Association
- Celeste Contín at the Billie Jean King Cup
- {{ITF profile}} template using deprecated numeric ID.