Be a positive real number sequence. With this the row is formed. This series should be examined for convergence or divergence.
Convergence statement
Is there a positive real number sequence so that from a certain index the expression
is always greater than or equal to a positive constant
, then the series converges .
Divergence statement
Is there a positive real number sequence
such that
the series of reciprocal terms diverges and
from a certain index the expression
is always less than or equal to zero,
then the series diverges .
proofs
Proof of the convergence statement
The estimate
applies to all indices
.
After multiplying with, this results in
.
This inequality can now be added up to any large natural number in the manner of a telescope sum.
The last term is always less than , this bound does not depend on . So applies to everyone
Therefore the sequence of partial sums grows monotonically from the index and is limited upwards. According to the (trivial) criterion of monotonic convergence, this converges
.
Proof of the divergence statement
The estimate
applies to all indices
and so too .
The inductive concatenation of these inequalities of up to an arbitrarily large index results
,
after further adjustment
.
If this inequality is added up to an arbitrarily large index , it follows
Last row diverges according to requirement for . So also diverges according to the minorant criterion .