Leskov Island (Antarctica)
| Leskov Island | ||
|---|---|---|
| Waters | Davissee | |
| Geographical location | 66 ° 36 '7 " S , 85 ° 11' 8" O | |
|
||
| length | 9 km | |
| width | 5.5 km | |
| surface | 49.5 km² | |
| Highest elevation | 180.01 m | |
| Residents | uninhabited | |
Leskov Island ( Russian Остров Лескова Ostrow Leskowa ) is an ice-covered and uninhabited island in the western ice shelf off the Leopold and Astrid coast of the East Antarctic Princess Elisabeth Land . It has an area of about 49.5 km², which corresponds to a length of about 9 km and a width of about 5.5 km. The highest point on the island is 180.01 m . Leskov Island is located about 6 km north-northeast of Mikhaylov Island .
The uninhabited island was discovered in 1956 by a Soviet Antarctic expedition. Namesake is Arkadi Sergejewitsch Leskow (1797-1858), third officer on the ship Vostok in the first Russian Antarctic expedition (1819-1821) under the direction of Fabian Gottlieb von Bellingshausen . The Advisory Committee on Antarctic Names translated the Russian designation into English in 1965.
Web links
- Leskov Island in the Geographic Names Information System of the United States Geological Survey (English)
- Leskov Island on geographic.org (English)