Sandusky Township (Crawford County, Ohio)

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Sandusky Township
Sandusky Township (Ohio)
Sandusky Township
Sandusky Township
Location in Ohio
Basic data
State : United States
State : Ohio
County : Crawford County
Coordinates : 40 ° 51 ′  N , 82 ° 49 ′  W Coordinates: 40 ° 51 ′  N , 82 ° 49 ′  W
Time zone : Eastern ( UTC − 5 / −4 )
Residents : 475 (status: 2000)
Population density : 10.2 inhabitants per km 2
Area : 46.5 km 2  (approx. 18 mi 2 ) of
which 46.5 km 2  (approx. 18 mi 2 ) is land
Height : 314 m
Area code : +1 419
FIPS : 39-70366
GNIS ID : 1085944
Map of Crawford County Ohio With Municipal and Township Labels.PNG
Crawford County's townships

Sandusky Township is one of 16 townships of Crawford County in the US state of Ohio . According to the census in 2000 , 475 inhabitants were registered here.

geography

Sandusky Township is located in east-east Crawford County in north-central Ohio and is bordered clockwise by the townships: Cranberry Township , Auburn Township , Vernon Township , Jefferson Township , Whetstone Township, and Liberty Township .

administration

The township is administered by a Board of Trustees consisting of three elected members. Two people are elected in the year after the presidential election and one in the year before. The term of office usually lasts four years and begins on January 1st. There is also a township clerk (responsible for finances and budget), which is also elected for a four-year term in the year before the presidential election. His term of office begins on April 1st.

Individual evidence

  1. Population figures at Factfinder.census.gov ( Memento from February 12, 2020 in the web archive archive.today )

Web links