where the value of the function defined for is at the point . Then for the series for sufficiently large (e.g. for ) either the inequality for convergence or that for divergence applies:
proof
The first inequality is satisfied. For each then applies with the substitution :
;
it follows:
,
because it applies:
,
the subtrahend in the second round bracket is positive. In this case:
Since the integral grows with increasing , it has for a finite limit :
;
according to the integral criterion , the series is thus convergent.
Now the second inequality is satisfied. Then:
and, if the integral is added to both sides :
(because because of is ). Now we form a sequence of numbers by stating ; according to what has been proven:
,
so:
.
So it is clear that:
holds, d. i.e., according to the integral criterion, the series is divergent.
literature
Gregor Michailowitsch Fichtenholz : Differential and integral calculus 2 (= university books for mathematics . Volume62 ). 10th edition. Verlag Harri Deutsch [Fismatgis / Физматгиз ], Frankfurt am Main [Moscow] 2009, ISBN 978-3-8171-1279-1 , XI: Infinite series with constant members , p.268/732 p . ( Limited preview in Google Book Search - Russian: Курс дифференциального и интегрального исчисления . Translated by Brigitte Mai, Walter Mai, first edition: 1959).
Individual evidence
↑ Worksheet I. (PDF; 155 kB) Lecture Analysis II (SoSe 2010). Institute for Analysis, Dynamics and Modeling (Faculty of Mathematics and Physics) at the University of Stuttgart, April 29, 2010, p. 3/8 p. , Accessed on December 24, 2012 .
^ Gregor Michailowitsch Fichtenholz : Differential- und Integralrechner 2 (= university books for mathematics . Volume62 ). 10th edition. Verlag Harri Deutsch, Frankfurt am Main 2009, ISBN 978-3-8171-1279-1 , XI: Infinite series with constant terms , p.268/732 p . ( Limited preview in Google Book Search [accessed December 24, 2012] Russian: Курс дифференциального и интегрального исчисления . Translated by Brigitte Mai, Walter Mai).