Huemul Island
| Huemul Island | ||
|---|---|---|
| Waters | Bransfield Street | |
| Archipelago | Palmer Archipelago | |
| Geographical location | 63 ° 41 ′ S , 60 ° 50 ′ W | |
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Huemul Island ( Spanish Islote Huemul , in the United Kingdom Megaptera Island ) is a small island in the Palmer Archipelago off the west coast of the Antarctic Peninsula . It is located off the north end of Trinity Island .
Participants of the Fifth French Antarctic Expedition (1908-1910) under the direction of polar explorer Jean-Baptiste Charcot mapped them. It was named during the 1st Chilean Antarctic Expedition (1946–1947). It is named after the Andean deer ( Huemul in Spanish ), which is also shown in the coat of arms of Chile . The Advisory Committee on Antarctic Names converted this designation into English in 1965. The namesake of the name made by the UK Antarctic Place-Names Committee in 1960, however, is the humpback whale ( Latin Megaptera novaeangliae ).
Web links
- Huemul Island in the Geographic Names Information System of the United States Geological Survey (English)
- Huemul Island on geographic.org (English)