Octyabrsky Peak

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Octyabrsky Peak
Oktyabrsky peak from the southeast

Oktyabrsky peak from the southeast

height 6780  m
location Mountain Badakhshan ( Tajikistan )
Mountains Transalai Mountains ( Pamir )
Dominance 8.15 km →  Lenin Peak
Notch height 970 m ↓  ( 5810  m )
Coordinates 39 ° 19 '45 "  N , 72 ° 58' 15"  E Coordinates: 39 ° 19 '45 "  N , 72 ° 58' 15"  E
Pik Oktjabrski (Tajikistan)
Octyabrsky Peak
First ascent 1955, Yevgeny Beletsky

The Pik Oktjabrski ( Russian Пик Октя́брьский , "October summit", referring to the October Revolution ) is one of the highest mountains in the central section of the Transalai chain in the northern part of the Pamir (Central Asia).

The 6780  m high mountain is 8.15 km east-south-east of Lenin Peak . It lies on a ridge branching off south of the main ridge of the Transalai, the southern continuation of which is the Zulumart chain . The branching point is the Pik Jedinstwa secondary peak, 2 km north-northwest . The Pik Oktjabrski is flanked in the west by the Great Saukdara Glacier and in the east by the Oktjabrski Glacier .

Ascent history

The mountain was first climbed in 1958 by a Soviet mountaineering group led by Yevgeny Beletsky .

Minor peaks

A mountain ridge leads from Pik Oktjabrski to Pik Jedinstwa ( Russian Пик Единства , " Peak of Unity" ⊙ ) located 2 km north-northwest, 6673  m high , which lies on the main ridge of the Transalai and on the border with Kyrgyzstan . The first ascent was made in 1955 under the leadership of Yevgeny Belezki.

Web links

Individual evidence

  1. ↑ a b Yevgeniy Gippenreiter, Vladimir Shataev: Six and Seventhousanders of the Tien Shan and the Pamirs (PDF 4.6 MB) Alpine Journal, 1996, 122-130.