São Francisco Xavier, Rio de Janeiro: Difference between revisions

Coordinates: 22°54′12″S 43°14′36″W / 22.90333°S 43.24333°W / -22.90333; -43.24333
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m WP:CHECKWIKI error fixes using AWB (9585)
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Migrate {{Infobox settlement}} coordinates parameters to {{Coord}}, see Wikipedia:Coordinates in infoboxes
 
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|image_caption =
|image_caption =
|image_map =
|image_map =
|pushpin_map = Brazil Rio de Janeiro#Brazil
|coordinates_display = inline,title
|coordinates_region = BR
|pushpin_map = Brazil Rio de Janeiro
|pushpin_map_caption = Location in Rio de Janeiro
|pushpin_map_caption = Location in Rio de Janeiro
|subdivision_type = [[List of sovereign states|Country]]
|subdivision_type = [[List of sovereign states|Country]]
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|timezone =
|timezone =
|utc_offset =
|utc_offset =
|coordinates = {{coord|22|54|12|S|43|14|36|W|region:BR|display=inline,title}}
|latd=22 | latm=54 | lats=12 | latNS = S
|longd=43 | longm=14 | longs=36 | longEW = W
|elevation_footnotes =
|elevation_footnotes =
|elevation_m =
|elevation_m =
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|footnotes =
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}}
}}

'''São Francisco Xavier ''' is a neighborhood in the [[Rio de Janeiro#North Zone|North Zone]] of [[Rio de Janeiro]], [[Brazil]].
'''São Francisco Xavier ''' is a neighborhood in the [[Rio de Janeiro#North Zone|North Zone]] of [[Rio de Janeiro]], [[Brazil]].


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{{Brazil-geo-stub}}
{{RiodeJaneiro-geo-stub}}

Latest revision as of 13:53, 24 March 2017

São Francisco Xavier
Neighborhood
São Francisco Xavier is located in Rio de Janeiro
São Francisco Xavier
São Francisco Xavier
Location in Rio de Janeiro
São Francisco Xavier is located in Brazil
São Francisco Xavier
São Francisco Xavier
São Francisco Xavier (Brazil)
Coordinates: 22°54′12″S 43°14′36″W / 22.90333°S 43.24333°W / -22.90333; -43.24333
Country Brazil
StateRio de Janeiro (RJ)
Municipality/CityRio de Janeiro
ZoneNorth Zone

São Francisco Xavier is a neighborhood in the North Zone of Rio de Janeiro, Brazil.