Newton scale
The Newton scale is a temperature scale proposed by Isaac Newton around the year 1700 . When Newton dealt with the problem area of heat , he developed the first qualitative temperature scale, which had around 20 points on the scale from "cold air in winter" to "glowing coals in the kitchen fire". This approach was crude and imprecise, so that Newton quickly became dissatisfied with it. Knowing the concept of thermal expansion , he used a vessel with linseed oil and measured its change in volume in relation to the earlier points on the scale. He found a volume increase of 7.25% between the temperature of melted snow and boiling water.
After a while he defined the zero point of his scale with melting snow ( melting point , 0 ° C) and the 33rd degree as boiling water ( boiling point , 100 ° C), so he used the same fixed points as the Celsius scale, only with different degrees. A difference of one degree Newton (1 ° N) therefore roughly corresponds to that of three degrees Celsius.
Temperature scales
unit | Unit symbol | lower anchor point F 1 | upper anchor point F 2 | Unit value | inventor | Year of creation | Distribution area |
---|---|---|---|---|---|---|---|
Kelvin | K |
Absolute zero point , T 0 = 0 K |
Now without a fixed point, originally later T Tri ( H 2 O ) = 273.16 K |
earlier |
William Thomson Baron Kelvin | 1848 | worldwide ( SI unit ) |
centigrade | ° C | Now 0 ° C = 273.15 K, previously T Schm (H 2 O) = 0 ° C |
Now coupling to Kelvin, previously T boiling (H 2 O) = 100 ° C |
earlier |
Different Celsius | 1742 | worldwide ( derived SI unit ) |
degrees Fahrenheit | ° F | Now 32 ° F = 273.15 K, originally T cold. = 0 ° F, later T Schm (H 2 O) = 32 ° F |
Now coupling to Kelvin, originally T human = 96 ° F, later T boiling (H 2 O) = 212 ° F |
originally later |
Daniel Fahrenheit | 1714 | United States |
Rankine degree | ° Ra, ° R | T 0 = 0 ° Ra | Now coupling to Kelvin | William Rankine | 1859 | United States | |
Degree Delisle | ° De, ° D | T Schm (H 2 O) = 150 ° De | T boiling (H 2 O) = 0 ° De | Joseph-Nicolas Delisle | 1732 | Russia (19th century) | |
Degree Réaumur | ° Ré, ° Re, ° R | T Schm (H 2 O) = 0 ° Ré | T boiling (H 2 O) = 80 ° Ré | René-Antoine Ferchault de Réaumur | 1730 | Western Europe until the end of the 19th century | |
Degrees Newtons | ° N | T Schm (H 2 O) = 0 ° N | T boiling (H 2 O) = 33 ° N | Isaac Newton | ≈ 1700 | none | |
Degree Rømer | ° Rø | T Schm ( Lake ) = 0 ° Rø | T boiling (H 2 O) = 60 ° Rø | Ole Romer | 1701 | none | |
Notes on the table:
|
Temperature conversion
→ from → |
Kelvin (K) |
Degrees Celsius (° C) |
Degrees Fahrenheit (° F) |
Rankine degree (° Ra) |
|
---|---|---|---|---|---|
↓ to ↓ | |||||
T Kelvin | = | T K | T C + 273.15 | (T F + 459.67) 5 ⁄ 9 | T Ra · 5 / 9 |
T Celsius | = | T K - 273.15 | T C | (T F - 32) 5 ⁄ 9 | T Ra · 5 / 9 - 273.15 |
T Fahrenheit | = | T K * 1.8 - 459.67 | T C * 1.8 + 32 | T F | T Ra - 459.67 |
T Rankine | = | T K * 1.8 | T C * 1.8 + 491.67 | T F + 459.67 | T Ra |
T Réaumur | = | (T K - 273.15) x 0.8 | T C x 0.8 | (T F - 32) 4 ⁄ 9 | T Ra · 4 / 9 - 218.52 |
T Rømer | = | (T K - 273.15) 21 ⁄ 40 + 7.5 | T C · 21 / 40 + 7.5 | (T F - 32) 7 ⁄ 24 + 7.5 | (T Ra - 491.67) 7 ⁄ 24 + 7.5 |
T Delisle | = | (373.15 - T K ) x 1.5 | (100 - T C ) x 1.5 | (212 - T F ) 5 ⁄ 6 | (671.67 - T Ra ) 5 ⁄ 6 |
T Newtons | = | (T K - 273.15) x 0.33 | T C x 0.33 | (T F - 32) 11 ⁄ 60 | (T Ra - 491.67) 11 ⁄ 60 |
→ from → | Degree Réaumur (° Ré) |
Degree Rømer (° Rø) |
Degree Delisle (° De) |
Degree Newton (° N) |
|
↓ to ↓ | |||||
T Kelvin | = | T Ré 1.25 + 273.15 | (T Rø - 7.5) 40 ⁄ 21 + 273.15 | 373.15 - T De · 2 / 3 | T N · 100 / 33 + 273.15 |
T Celsius | = | T Ré 1.25 | (T Rø - 7.5) 40 ⁄ 21 | 100 - T De · 2 / 3 | T N · 100 / 33 |
T Fahrenheit | = | T Ré · 2.25 + 32 | (T Rø - 7.5) 24 ⁄ 7 + 32 | 212 - T De 1.2 | T N · 60 / 11 + 32 |
T Rankine | = | T Ré · 2.25 + 491.67 | (T Rø - 7.5) 24 ⁄ 7 + 491.67 | 671.67 - T De * 1.2 | T N · 60 ⁄ 11 + 491.67 |
T Réaumur | = | T Ré | (T Rø - 7.5) 32 ⁄ 21 | 80 - T De · 8 / 15 | T N · 80 / 33 |
T Rømer | = | T Re · 21 / 32 + 7.5 | T Rø | 60 - T De 0.35 | T N · 35 / 22 + 7.5 |
T Delisle | = | (80 - T Ré ) · 1.875 | (60 - T Rø ) 20 ⁄ 7 | T De | (33 - T N ) 50 ⁄ 11 |
T Newtons | = | T Re · 33 / 80 | (T Rø - 7.5) 22 ⁄ 35 | 33 - T De · 0.22 | T N |