Jefferson Township (Ashtabula County, Ohio)

Jefferson Township
Jefferson Township Location in Ohio
Basic data
State :	United States
State :	Ohio
County :	Ashtabula County
Coordinates :	41 ° 45 ′  N , 80 ° 46 ′  W Coordinates: 41 ° 45 ′  N , 80 ° 46 ′  W
Time zone :	Eastern ( UTC − 5 / −4 )
Residents :	5,559 (as of: 2000)
Population density :	83.2 inhabitants per km 2
Area :	67.0 km 2  (approx. 26 mi 2 ) of which 66.8 km 2  (approx. 26 mi 2 ) are land
Height :	276 m
Postal code :	44047
Area code :	+1 440
FIPS :	39-38514
GNIS ID :	1085729
Ashtabula County's townships

Jefferson Township is one of 27 townships of Ashtabula County in the US state of Ohio . According to the census in 2000 , 5559 inhabitants were registered here.

geography

Jefferson Township is located north of the geographic center of Ashtabula County in the extreme northeast of Ohio, is about 15 km to the north from Lake Erie and borders the townships in a clockwise direction: Plymouth Township , Sheffield Township , Denmark Township , Dorset Township , Lenox Township , Morgan Township , Austinburg Township and Saybrook Township .

administration

The township is administered by a Board of Trustees consisting of three elected members. Two people are elected in the year after the presidential election and one in the year before. The term of office usually lasts four years and begins on January 1st. There is also a township clerk (secretary), who is also elected for a four-year term in the year before the presidential election. His term of office begins on April 1st.

Individual evidence

1. ↑ Population figures at Factfinder.census.gov ( Memento from February 12, 2020 in the web archive archive.today )