Election to the United States House of Representatives in 1844

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Starting July 1, 1844, the House of Representatives was elected on various election days in the United States . The election was part of the general election for the 29th United States Congress that year, in which a third of the US Senators were also elected. At the same time the presidential election of 1844 took place, which was won by the Democrat James K. Polk .

At the time of the election, the United States consisted of 27 states ( Florida was now a new addition). The number of MPs to be elected was 228. The distribution of seats in the House of Representatives was based on the 1840 census . In the elections, the United States Whig Party had a slight gain of 7 seats while the Democrats lost 5 seats. Their clear absolute majority, however, remained. For the Whigs, it was only a slight recovery from their major electoral defeat two years earlier. For the first time, the American Party moved into the House of Representatives with six MPs.

Women and slaves were neither eligible nor eligible to vote. Free African Americans were also excluded from voting in many states .

Election result

Total: 228

The results of the last election two years earlier are in brackets. Changes in the course of the legislative period that do not affect the elections themselves are not included in these figures, but are noted in the article on the 29th Congress in the section on the members of the House of Representatives under the corresponding names of the representatives. The same applies to elections in states that did not join the Union until after the beginning of the legislative period. As a result, the sources sometimes contain different information, as changes during the legislative period were sometimes incorporated into the figures and sometimes not.

See also

Web links