Election to the United States Senate in 1994
On November 8, 1994 , one-third of the members of the United States Senate were elected in the United States . The election was part of the general election that year, in which all members of the House of Representatives were also elected.
Each of the 50 states has 2 representatives in the Senate. Under the United States Constitution , US Senators are elected for six years. However, all members of the Senate are never elected at the same time. The election follows a scheme according to which a third of the senators are elected every two years at the same time as the election to the US House of Representatives. For this purpose, the Senate is divided into three classes , which determine the election year of the Senators. In 1994 the Senators of Class I stood for election.
Before the election, 53 senators were Democrats and 47 were Republicans. The election result showed a shift in favor of the Republicans, who now achieved a majority in the Senate of 52 seats. With 48 seats, the Democrats only had the role in the opposition. The ratio of numbers changed in the course of the legislative period through party converts and a by-election to 53:47 for the Republicans, which reversed the previous majority.
Results and course of the legislative period
Political party (Shading shows majority party)
|
Total | |||
---|---|---|---|---|
republican | Democrats | Vacant | ||
End of the 103rd Congress | 47 | 53 | 100 | 0 |
Beginning | 53 | 47 | 100 | 0 |
The End | ||||
Final voting ratio | 53.0% | 47.0% | ||
Beginning of the 105th Congress | 55 | 45 | 100 | 0 |
The exact results of the November 8, 1994 election:
Democrats: 25,234,942 votes (44.0%) 48 seats (later 47)
Republicans: 28,613,349 votes (49.9%) 52 seats (later 53)
Other: 3,457,190 votes (6.1%) no seats