Election to the United States Senate in 1928

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On November 6, 1928, or September 10 in the state of Maine , one-third of the members of the United States Senate were elected. The election was part of the general election to the 71st United States Congress that year, in which all members of the House of Representatives were also elected. The 1928 presidential election , won by Republican Herbert Hoover , also took place at the same time .

Since the adoption of the 17th Amendment to the United States Constitution in 1913, all US senators in their respective states have been directly elected by the people of their state. Each state has 2 senators. Under the United States Constitution , US Senators are elected for six years. However, all members of the Senate are never elected at the same time. The election follows a scheme according to which a third of the senators are elected every two years at the same time as the election to the US House of Representatives. For this purpose, the Senate is divided into three classes , which determine the election year of the Senators. In 1928 the Senators of Class I stood for election. At that time, the United States consisted of 48 states. This results in a total of 96 senators, 35 of whom stood for election. There was a clear victory for the Republicans, who took eight seats from the Democrats. One of the reasons for this was the positive economic development at that time, which was to last until 1929 and which many voters brought into connection with the politics of the Republican federal government at the time.

Senate composition after the election

Total: 96

The results of the last elections on November 2, 1926 are in brackets. Changes in the course of the legislative period that do not affect the elections themselves are not included in these figures. But are noted in the article on the 71st Congress in the section on the members of the Senate by the corresponding names of the senators.

See also