Romanian football championship 1927/28

Romanian football championship 1927/28
master	Colțea Brasov
Teams	12
Games	11
Gates	67  (ø 6.09 per game)
← Romanian football championship 1926/27 Romanian Football Championship 1928/29 →

The finals of the Romanian Football Championship 1927/28 took place from June 24th to July 29th, 1928. The participants who played for the championship in the knockout system were determined in twelve regional preliminary rounds. There was only one game at a time. If no decision could be reached even after extra time, a replay took place the next day at the same location. Champion was Colțea Brașov after the defending champion Chinezul Timișoara was eliminated in the quarterfinals.

Attendees

region	winner
Arad	Jiul Lupeni
Brașov	Colțea Brasov
Bucharest	Olimpia Bucharest
Cernăuți	Polonia Czerniowce
Chișinău	Mihai Viteazul Chișinău
Cluj	România Cluj
Craiova	Craiovan Craiova
Galați	Dacia Vasile Alecsandri Galați
Iași	Concordia Iași
Oradea	Stăruința Oradea
Sibiu	Șoimii Sibiu
Timișoara	Chinezul Timișoara

Results

Preliminary round

	Result
Dacia Vasile Alecsandri Galați	2: 4 n.V. (2: 2, 1: 1)	Olimpia Bucharest
România Cluj	3: 2 (2: 2)	Stăruința Oradea
Craiovan Craiova	2: 4 (2: 2)	Șoimii Sibiu
Mihai Viteazul Chișinău	9: 1 (5: 0)	Concordia Iași

Quarter finals

	Result
Mihai Viteazul Chișinău	5: 2 (2: 1)	Polonia Czerniowce
Olimpia Bucharest	2: 3 n.V. (2: 2, 0: 1)	Colțea Brasov
Șoimii Sibiu	2: 2 n.V. (2: 2, 1: 2)	Chinezul Timișoara
România Cluj	0: 2 (0: 0)	Jiul Lupeni

Replay

	Result
Șoimii Sibiu	4: 3 n.V. (3: 3, 0: 2)	Chinezul Timișoara

Semifinals

	Result
Colțea Brasov	6: 4 (3: 2)	Mihai Viteazul Chișinău
Jiul Lupeni	1	Șoimii Sibiu

¹ Sibiu did not run.

final

	Result
Colțea Brasov	3: 2 (2: 1)	Jiul Lupeni

Web links

• Season 1927/28 on romaniansoccer.ro (English)