John Joseph Seerley

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John Joseph Seerley (born March 13, 1852 in Toulon , Stark County , Illinois , † February 23, 1931 in Burlington , Iowa ) was an American politician . Between 1891 and 1893 he represented the state of Iowa in the US House of Representatives .

Career

In 1854, John Seerley came to Iowa with his parents. The family settled on a farm in Keokuk County , where the boy attended public schools. He then studied until 1875 at the University of Iowa . In 1876, he worked as a high school teacher in Iowa City . After a subsequent law degree, which he also completed at the University of Iowa, and his admission as a lawyer in 1877, he began to practice in Burlington in his new profession. Between 1885 and 1890 he was a litigator for the City of Burlington.

Seerley was a member of the Democratic Party . In 1888 he ran for a seat in Congress for the first time unsuccessfully against the Republican John Gear . Two years later he was elected against Gear in the first constituency of Iowa in the US House of Representatives in Washington, DC , where he replaced it on March 4, 1891. But since he lost again to Gear in the next election in 1892, Seerley could only complete one legislative period in Congress until March 3, 1893.

Between 1893 and 1895, Seerley was again an attorney for the city of Burlington. Otherwise he worked again as a lawyer. He also got into banking and was involved in agriculture. In 1920 Seerley was a delegate to the Democratic National Convention in San Francisco . He died in Burlington in February 1931 and was buried there.

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personal data
SURNAME Seerley, John Joseph
BRIEF DESCRIPTION American politician
DATE OF BIRTH March 13, 1852
PLACE OF BIRTH near Toulon , Illinois
DATE OF DEATH February 23, 1931
Place of death Burlington , Iowa